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Table 2 Unadjusted and adjusted logistic regression odds ratios (UOR/AOR) between Victorian-born cases and controls for selected phenotypic ‘exposure’ variables

From: CLARITY – ChiLdhood Arthritis Risk factor Identification sTudY

  UOR (95% CI) AOR (95% CI)
   Mother’s SEIFA score Child measures† Mother’s age at child’s birth
Mother’s SEIFA score* 1.01 (1.00, 1.01), p = 0.003 ** 1.01 (1.00, 1.01), p = 0.004 1.01 (1.00, 1.01), p = 0.011
Mother completed Yr12 0.86 (0.61, 1.22), p = 0.39 1.02 (0.55, 1.88), p = 0.95 2.95 (1.30, 6.68), p = 0.009 2.72 (1.19, 6.20) p = 0.017
Father completed Yr12 0.86 (0.61, 1.20), p = 0.37 0.64 (0.37, 1.11), p = 0.11 1.05 (0.55, 1.98), p = 0.89 0.98 (0.51, 1.86), p = 0.94
Mother married at interview 1.71 (1.15, 2.52), p = 0.007 1.82 (0.96, 3.45), p = 0.065 2.94 (1.32, 6.57), p = 0.009 2.62 (1.16, 5.92), p = 0.020
Father married at interview 1.67 (1.08, 2.59), p = 0.022 2.11 (1.02, 4.39), p = 0.044 2.78 (1.20, 6.43), p = 0.017 2.48 (1.06, 5.80), p = 0.036
Mother hours in paid work* 1.01 (1.00, 1.02), p = 0.12 0.99 (0.98, 1.01), p = 0.40 0.98 (0.96, 1.00), p = 0.078 0.98 (0.96, 1.00), p = 0.037
Father hours in paid work* 1.01 (1.00, 1.02), p = 0.23 1.01 (0.99, 1.03), p = 0.50 1.02 (0.99, 1.04), p = 0.17 1.02 (0.99, 1.04), p = 0.16
Mother currently smokes 0.68 (0.46, 1.00), p = 0.049 0.45 (0.22, 0.92), p = 0.029 0.25 (0.095, 0.63), p = 0.003 0.27 (0.11, 0.71), p = 0.008
Father currently smokes 0.65 (0.44, 0.97), p = 0.036 0.68 (0.36, 1.30), p = 0.25 0.69 (0.34, 1.41), p = 0.31 0.80 (0.39, 1.64), p = 0.54
Mother’s age at child’s birth* 1.05 (1.02, 1.08), p = 0.002 1.07 (1.01, 1.12), p = 0.016 1.08 (1.02, 1.15), p = 0.011 **
Father’s age at child’s birth* 1.04 (1.01, 1.07), p = 0.009 1.04 (1.00, 1.09), p = 0.067 1.06 (1.01, 1.11), p = 0.025 **
Mother smoked during child’s pregnancy (any) 0.56 (0.37, 0.85), p = 0.007 0.77 (0.41, 1.45), p = 0.43 0.52 (0.24, 1.12), p = 0.094 0.61 (0.28, 1.33), p = 0.21
Father smoked during child’s pregnancy (any) 0.61 (0.41, 0.91), p = 0.015 0.52 (0.26, 0.97), p = 0.039 0.42 (0.20, 0.89), p = 0.024 0.46 (0.21, 0.99), p = 0.047
Mother took Vitamin D during child’s pregnancy 0.45 (0.21, 1.00), p = 0.05 0.16 (0.02, 1.21), p = 0.075 0.21 (0.03, 1.69), p = 0.14 0.26 (0.03, 2.10), p = 0.21
Mother took fish oil during child’s pregnancy 0.42 (0.17, 1.04), p = 0.06 0.45 (0.10, 1.99), p = 0.29 0.71 (0.15, 3.36), p = 0.66 0.70 (0.15, 3.33), p = 0.65
Mother drank alcohol during child’s pregnancy (any) 1.07 (0.71, 1/62), p = 0.74 0.72 (0.35, 1.48), p = 0.37 1.07 (0.50, 2.35), p = 0.85 0.97 (0.44, 2.16), p = 0.94
Mother drank coffee during child’s pregnancy (any) 1.13 (0.82, 1.57), p = 0.46 0.85 (0.51, 1.42), p = 0.53 0.67 (0.37, 1.21), p = 0.19 0.66 (0.36, 1.22), p = 0.19
Child was breastfed (any) 1.46 (0.94, 2.29), p = 0.094 0.88 (0.44, 1.73), p = 0.70 0.90 (0.41, 1.97), p = 0.79 0.86 (0.39, 1.89), p = 0.71
Length of breastfeeding (if any, weeks)* 1.00 (0.99, 1.00), p = 0.70 1.00 (1.00, 1.01), p = 0.19 1.01 (1.00, 1.01), p = 0.25 1.00 (0.99, 1.01), p = 0.72
Age at commencement of cow’s milk (weeks)* 0.99 (0.98, 1.00), p = 0.043 1.00 (0.99, 1.01), p = 0.88 0.99 (0.98, 1.01), p = 0.45 0.99 (0.98, 1.01), p = 0.30
Mother smokes indoors near child (any) 0.55 (0.25, 1.21), p = 0.14 0.49 (0.21, 1.10), p = 0.082‡ 0.32 (0.10, 1.01), p = 0.052 0.33 (0.10, 1.06), p = 0.063
Father smokes indoors near child (any) 0.51 (0.22, 1.18), p = 0.12 0.52 (0.22, 1.23), p = 0.14‡ 0.22 (0.07, 0.67), p = 0.008 0.26 (0.08, 0.81), p = 0.020
  1. Covariates were added to the logistic regression model sequentially from left to right.
  2. Phenotypic variables that remained significantly different between cases and controls following full covariate adjustment are highlighted in bold.
  3. †Child measures = age, sex, Caucasian ancestry (y/n).
  4. *β coefficients reported for continuous exposures.
  5. ** Not adjusted for since same as, or highly significantly correlated with, the exposure variable.
  6. ‡ Mother’s completion of high school used in the model as a proxy for mother’s SEIFA score (correlation: r = 0.24, p < 0.0001) due to insufficient data for SEIFA.